You are using fast parts, and they will have very high frequency components in the output signals defined by the transition time not the clock period.
If you are using solderless breadboards, you will fail due to the inductance of all the interconnection wires.
If you are not using solderless breadboards, you may still fail unless you have decoupling capacitors plus direct connections (not wires, and preferably a continuous ground plane).
Realise a wire is L=1nH/mm, then do the calculation of V=Ldi/dt and realise that V is added/subtracted to signal voltages. dt is the transition time (probably 1ns or less) and di=3.3C/dt, where C is the a load capacitance (assume 10pF) and 3.3 is the voltage swing.