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Fourier Series analysis of Triangular waveform
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Topic: Fourier Series analysis of Triangular waveform (Read 1226 times)
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khatus
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Fourier Series analysis of Triangular waveform
«
on:
February 13, 2019, 03:08:56 pm »
Fourier Series of Triangular waveform
this is the solution of Fourier series of a triangular waveform from the book Circuits and Networks: Analysis and Synthesis by Shyammohan S. Palli.
In this problem they have take the time period of the triangular waveform from -π to +π instead of 0 to 2π.
Now, from -π to 0 the equation of the waveform is as shown below
and from 0 to +π the equation of the waveform is
Which gives
My question is,
If i take the interval from 0 to 2π.then from 0 to +π the equation of the waveform will be
and from +π to +2π the equation of the waveform will be
But this gives
which did not match with previous.My question is why they took the interval from -π to +π instead of 0 to 2π.
I post my calculation here
«
Last Edit: February 13, 2019, 03:23:45 pm by khatus
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Andy Watson
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Re: Fourier Series analysis of Triangular waveform
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Reply #1 on:
February 13, 2019, 03:57:00 pm »
Check the limits on your last integration and note that the upper limit is \$2\pi\$ - when you run the figures this should translate to \$(2\pi)^2\$, you appear to have used \$2(\pi^2)\$.
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Last Edit: February 13, 2019, 03:58:55 pm by Andy Watson
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Wimberleytech
khatus
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Re: Fourier Series analysis of Triangular waveform
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Reply #2 on:
February 13, 2019, 04:33:03 pm »
Thanks
Andy Watson
.silly mistake causes problem
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rhb
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Re: Fourier Series analysis of Triangular waveform
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Reply #3 on:
February 16, 2019, 02:05:02 am »
Because the discrete Fourier transform is periodic over the semi-closed interval from (-Pi,Pi] by definition.
I had a very miserable couple of weeks at work because I overlooked the semi-closed part.
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