I don't know how to approach a analog switch. Say there is an op-amp voltage follower with a analog switch on it that shorts the input to another follower (shunt resistance)
How does the noise on the op amp sees on the input change when the switch is open and closed? How about the op-amp with the switch (that is in series with the input now, so its like a series resistance)
The analog switch has a xnV/hz noise. (probobly like 3nV/hz realistically)
Can someone explain what happens to the op-amps in each situation (series switch vs shunt switch open vs closed). I think that explaining this stupid puzzle will greatly benefit me.
the signal being fed into the beginning of this circuit is also a voltage follower.
like this
where the two top op amps are connected to eachother with a wire, the analog switch (cmos) only connects an additional OPA as a "load"
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