Would this be the correct format for the schematic? I was sure how to handle the split.
Your initial diagram made it easy to be confused. This new one is much improved. I don't know if this new drawing will pass expert's opinion (since I am just another hobbyist with limited experience), but I think it sure would help you think about the problem.
If you write down the same voltage you measured, you can now following it easier.
For example, in your
original diagram, the red dot left of R1 and the red dot to the right of R4 are actually the same point electrically speaking - since they are directly connected by (ideally 0-ohm) wire. It would still be the same point if you put the dot right under R5.
I bet you you've a mistake there: The dot you have
above R5 is actually
below R5. Above R5, you are directly connected to the black dot ground. So, it should read 0V. Below R5, that is the same electrical point as left-of-R1 and right-of R4 described above, so they are all at 6.34V.
That said, lets go around your diagram and see if I can help you understand how that flows (using your original diagram and not the redrawn one since your original has voltage written down) :
Right-of-R2 is connected to +7v, so at +7V it is.
Left-of-R2 is 6.38V -> R2 dropped (7V-6.38V) = 0.62V
*** This tells you your current running through R2 is
I=V/R=0.62V/148.5ohm=0.004175Amp
Right of R1 is 6.34V, Left of R1 is 6.38V, so R1 dropped 6.38V-6.34V=0.04V.
*** current thought R1 is
I=V/R=0.04V/10ohm = 0.004Amp
The current that flows through R1 and R2 should be the same (kirchoff's law) - even without known the law, common sense would say, the current can't disappear, they must be the same since they are inline with each other. Think of that as two connected garden hose R1 and R2. What goes through garden hose R1 and garden host R2 should be the same unless you have a leak.
Knowing they should be the same, but they are not - you have 0.004 on one and 0.004175 on the other. That is your system's error: perhaps measurement error, perhaps your resisters has resistance different than labeled.
.000174/0.004=0.043750 => your error there is is 4.375 percent. Well within the typical expectation.
Notice I did not say current through R5 would be the same at about 0.004Amp - they are not. Current from the right side with R3 and R4 also go through R5. So, whatever is going through R3, it is the same as through R4. That two "hose" joins up with the R1-R2 hose. So, R3-R3 current, plus current through R1-R2 would be the current going through R5.
Another thing you can surmise quickly is, R3-R4 side should have less current than R1-R2 side. There is more resistance on the R3-R4 side.
I hope this helps you see how current is flowing in your system, and how voltage is dropping in your system. Take the time to evaluate the R3-R4 side, see how much current actually is going through. Doing that exercise will have you in the future.
Rick