At 3000 Hz, the impedance of the cap and inductor are equal in magnitude but opposite in sign- they sort of a cancel. Since the L and C is in parallel, the combined impedance would go to infinity with no resistance in circuit. 1/Z = 1/z1 + 1/-z1, leads to a Z of infinity and a very peaky response. This doesn't happen due to R's in the circuit though quartz crystals come close with Q's of many thousands. The Q of a resonator is the fractional bandwidth that it is resonate over. It is a also equal to the loss in the resonator per cycle. With no R, Q would be infinite and the bandwidth would be zero and once you tickled the part, it would go forever. Think tuning fork. So if the Q of the resonator is about 10 - this is 300 hz wide 3 db bandwidth. The impedance of the cap is 1/2*pi*f*c= -j2123 ohms. The -j means that its complex, the inductor would have the same impedance but positive- they cancel. To make a Q of 10, add a parallel R of 212 ohms- my 500 was an approximation before knonwing much. You can sweep the circuit in spice and see all the magic. The R is a loss, it can go in parallel with both the L and C or in series with either component but in the loop. What a resonator does is slosh energy back and force between the two reactances. The R is a loss term and it burns some power on each "slosh" so has to be in the loop between the L and C, either parallel to both or more usually lumped with the L or C which is really the case.
Hope this makes sense- have fun