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Actually my application has a high output voltage therefore it's more desirable to not have the output choke, so moving that inductor to the input could prove advantageous. The resonant bridge is parallel loaded, and runs slightly above the peak resonant frequency and is fixed.
Everyone seems to think having a choke in the output filter of a HV supply is awful - usually assuming there will be a problem with insulation breakdown - but the same consideration applies to the secondary winding of the transformer. Maybe the choke will end up needing less turns - and therefore have to support a higher V/turn - but one usually has considerable freedom in selecting the core size and gap (distributed or discrete) for the choke, anyway.
At any rate, the phrase, "parallel-loaded," only partially describes the type of resonant topology; you also need to specify whether it is a series or parallel resonant network.
Is there any benefits to the hard-switched current fed bridge topologies? I assume they will be much simpler to design, however hard switching might be quite inefficient. I do plan on investigating the use of Gallium nitride switches so a hard-switched topology might not actually be a bad idea.
Hard-switched is easier to get design, easier to get working, and capable of a much wider load range than most (if not all) resonant topologies. That said, resonant converters can be immensely helpful in minimizing corona formation in high voltage supplies. Whether I'd strongly lean towards one or the other would depend on power level, output voltage, load current range, does it need to tolerate an open and/or short circuited load, etc.
Could I ask, what are the benefits and drawbacks to the two methods you describe? My plan was to use current mode control of the buck inductor and VMC of the secondary side with the optocoupler as you described.
Briefly (not comprehensively): taking feedback from the output of the buck converter means no isolation barrier is required for the feedback signal which means much faster transient response but less accurate control of the actual voltage on the secondary of the bridge converter; invert those pluses and minuses if taking feedback from the secondary of the bridge.
I understand your point about the buck converter, but isn't the efficiency of a synchronous buck always going to be more efficient? Since the conduction losses are related to I_o^2*Rds_on, if we choose a switch with low Rds_on.
Nope. There no guarantee a synchronous buck will be more efficient. In fact, the opposite is often the case, especially at partial loads, and/or when output voltage greater than half the input voltage. The two main reasons are higher total switching losses for the sync. rectifier, especially compared to a Schottky, and operation in "forced" continuous conduction mode all the way down to near zero load which increases conduction losses in the buck switch and inductor at light loading (when the buck inductor would go discontinuous).