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Ideal diode circuit confusion

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Zero999:
It's not an ideal diode circuit, which is a bit more complicated.
https://www.analog.com/media/en/technical-documentation/tech-articles/lt-journal-article/LTJournal-V26N4-01-df-LTC4357_59-MeilissaLum.pdf

Vovk_Z:

--- Quote from: kernels on January 21, 2020, 12:18:43 am ---But the 10V is on the drain of the left mosfet, not on the source, the two sources are tied together without any other connection.

--- End quote ---
+10 V is on the source of the left mosfet. And two drains are connected together.
And, as it was said, it isn't an ideal diode, it is just an electronic switch.

kernels:
Nope, as I said, they are N-channel Mosfets. And thanks, yeah, I know the circuit does not function as an ideal diode, I was only experimenting with the switch part of the ideal diode circuit since I intend to drive them myself. I note that the ideal diode controllers tend to have a wire to the common source pins, so was trying to figure out why they have that when it appears you can do the switching without it. It may be that you can switch them faster with a connections to the common sources.

kernels:
Sorry ! , I see the confusion, the online schematic package I was using didn't show the body diode as part of the mosfet, so I drew it in manually, but showed the two mosfets themselves reversed!  :palm:  Vovk_z sorry, you were right, I had built the circuit with common sources, but when drawing the schematic to post it here I reversed them.

Vovk_Z:
Yes, real dual mosfet switch has sources connected together.

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