Electronics > Beginners
IGBTs for Electronic Loads?
t1d:
I have never used IGBTs, so I watched this Great Scott video.
He says (@ 6:33) IGBTs can handle higher voltage and current than MOSFETs. That made me wonder if they might be better for E-loads than MOSFETs. What do I need to consider?
Thanks for the education!
T3sl4co1l:
Check the SOA, an [analog] electronic load needs DC SOA.
IGBTs have the smallest dies of all silicon transistors = lowest power dissipation for a given rating, besides other characteristics that make them undesirable in such service.
Despite that, I have surprisingly seen some IGBTs with DC SOA curves. I guess if you want to...
Tim
Berni:
It is possible if you get just the right kind of IGBT, otherwise no.
Most power IGBTs(And also MOSFETs) out there are actually internally built in the form of a large arrays of tiny transistors on the same die. Unfortunately IGBTs are particularly temperature and tolerance sensitive so when operated in the linear region the many tiny transistors inside will not share the load evenly, causing some small areas to get hotter that causes them to turn on even more and take more current, get even hotter...etc going into a thermal runaway until one small spot overheats and destroys the transistor. All this can happen at only a fraction of the rated dissipated power. Similar thing can happen with MOSFETs that are heavily optimized for switching operation.
Usually MOSFETs are less sensitive to this hotspot thermal runaway and so are better suited for DC operation. If a given MOSFET is designed for being operated at DC then the Safe Operating Area (SOA) will show a curve for DC on it and usually this will be mentioned on the first page of the datasheet along with perhaps calling it a Linear FET. Usually such FETs are significantly more expensive as they are more difficult to produce and generally require larger silicon dies
But a transistor won't instantly blow up on DC if it has no DC SOA specified in the datasheet. Some switching transistors are runaway resilient enough that they actually work just fine in a wide linear region. The manufacturer won't grantee this so you have to buy about 10 to 100 of these transistors and stress test them in your own lab all the way to destruction to find out how far up the SOA chart you can get before they explode. There are a few transistor part number out there that are known to be good at this.
t1d:
--- Quote from: Berni on November 27, 2019, 06:51:26 am ---Most power IGBTs(And also MOSFETs) out there are actually internally built in the form of a large arrays of tiny transistors on the same die. Unfortunately IGBTs are particularly temperature and tolerance sensitive so when operated in the linear region the many tiny transistors inside will not share the load evenly, causing some small areas to get hotter that causes them to turn on even more and take more current, get even hotter...etc going into a thermal runaway until one small spot overheats and destroys the transistor. All this can happen at only a fraction of the rated dissipated power. Similar thing can happen with MOSFETs that are heavily optimized for switching operation.
--- End quote ---
Good info. Thanks!
David Hess:
--- Quote from: T3sl4co1l on November 27, 2019, 05:56:24 am ---Despite that, I have surprisingly seen some IGBTs with DC SOA curves. I guess if you want to...
--- End quote ---
Since it is not something they are designed for, they are not tested for DC SOA so I would not trust the DC SOA curve unless the manufacturer specifically discussed it.
Navigation
[0] Message Index
[#] Next page
Go to full version