Electronics > Beginners
Inductor rise time questions!
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ZeroResistance:
So, let's say I have a
C = 1uF
L = 100uH
RL = 0.5 ohm (which I will ignore for this case)

and
1. Vc = 100V and I discharge this capacitor into the inductor and next
2. Vc = 500V and I discharge the capacitor into the inductor.

I would expect that as per the equation VL = L. di/dt. The rate of change of current di/dt is proportional to the ratio VL/L and since L is constant the rate of change of current should increase with V.

However for both cases I find (in LTspice) that the current reaches the peak value at the same time. I mean same rise time of current for both cases is the same.

I was expecting the case with the high Voltage to reach the peak current value earlier.
What am I doing wrong here or is my understanding wrong in this case?!

Thanks in advance!
Benta:
A sketch of your RLC connection would help. Right now I'm ????????
bson:
VL drops 5x as fast with the higher voltage, so while di/dt starts higher it also drops correspondingly faster.
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