Author Topic: Inductor rise time questions!  (Read 809 times)

0 Members and 1 Guest are viewing this topic.

Offline ZeroResistanceTopic starter

  • Frequent Contributor
  • **
  • Posts: 585
  • Country: gb
Inductor rise time questions!
« on: September 17, 2018, 06:54:08 pm »
So, let's say I have a
C = 1uF
L = 100uH
RL = 0.5 ohm (which I will ignore for this case)

and
1. Vc = 100V and I discharge this capacitor into the inductor and next
2. Vc = 500V and I discharge the capacitor into the inductor.

I would expect that as per the equation VL = L. di/dt. The rate of change of current di/dt is proportional to the ratio VL/L and since L is constant the rate of change of current should increase with V.

However for both cases I find (in LTspice) that the current reaches the peak value at the same time. I mean same rise time of current for both cases is the same.

I was expecting the case with the high Voltage to reach the peak current value earlier.
What am I doing wrong here or is my understanding wrong in this case?!

Thanks in advance!
 

Offline Benta

  • Super Contributor
  • ***
  • Posts: 6420
  • Country: de
Re: Inductor rise time questions!
« Reply #1 on: September 17, 2018, 08:52:43 pm »
A sketch of your RLC connection would help. Right now I'm ????????
 

Offline bson

  • Supporter
  • ****
  • Posts: 2497
  • Country: us
Re: Inductor rise time questions!
« Reply #2 on: September 17, 2018, 09:21:37 pm »
VL drops 5x as fast with the higher voltage, so while di/dt starts higher it also drops correspondingly faster.
 


Share me

Digg  Facebook  SlashDot  Delicious  Technorati  Twitter  Google  Yahoo
Smf