Yes you need the supply.
The OTA alias operational transconductance amplifier is simple to explain.
OTA circuits just work differently than OPA Circuits.
OTA circuits do not rely on feedback, that results in both inputs being at same voltage.
Instead you have a voltage difference at the inputs.
The output of the OTA is a current. That is is what transconductance means: voltage in, current out. Usually the transconductance is denoted as gm (m lowerscript) the fun thing with OTA´s is, that gm is not fix, but you can control it by changing the Ibias control current.
In case you connect a resistor between output and ground your OTA circuit gets a voltage amplifier. And in your case with Capacitor at output the circuit becomes an integrator. That easy way to build integrator stages, adjustable about typically 7 decades with Ibias is what makes OTA fun for oscillators, filters and the like. It is also very easy to do things like AGC (Automated Gain Control) Circuits.
OTA circuits are very common within analog integrated circuits, so there is a lot of more detail in special literature on analog IC Design. On Board level however they are less common. Except niche like audio effect circuits. Best you study the datasheets / application notes.
LM13700 datasheet is good start, contains many example circuits.
Main plot to understand is figure 8.
Example: you have 100mV at input, and Ibias is 10µA and 1k load resistor.
from figure 8 you get about 200µmho whith mho a funny way to denote 1/ohm also known as Siemens - unit of conductivity
so 100mV * 200µmho * 1kohm
the ohm and mho shorten, as well as m and k,
so 100V * 200µ = 20mV
not really impressive, but you could drive Ibias at 1000µA and would get 2V
Now change the resistor load to capacitor load and calculate
Uout = 1/C*Integral(I(t)), where I(t) is gm(Ibias(t))*Uin(t)