EEVblog Electronics Community Forum
Electronics => Beginners => Topic started by: sspj9 on February 03, 2016, 06:17:51 pm
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Hi,
I designed a JFET to output a constant current of 10mA for an assignment. Using 2N3819 with Vdd 20 V, we assumed that Vg is 4V, however we need to explain to why we set it to 4V. I mean we could set it to any value right and just change the resistors. Can anyone help?
Thanks.
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Not sure, the other way of asking the question is explain why you chose the resistors, presumably you have cme up with a suitable compromise of resistors and Vgs
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This Vishay App note might be of some help to you:
http://www.vishay.com/docs/70596/70596.pdf (http://www.vishay.com/docs/70596/70596.pdf)
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2N3819 isn't a very good choice for this... in most cases, Vg would need to be forward biased.
Tim
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"...because it works...." ?
:-//
No, I guess that answer might be ok in a physics class, but probably not in an engineering class.