Author Topic: LM317 Power Supply Design. (SOLVED)  (Read 3680 times)

0 Members and 1 Guest are viewing this topic.

Offline Mint.Topic starter

  • Frequent Contributor
  • **
  • Posts: 523
  • Country: au
  • Account is inactive now. Thanks everybody!
    • Personal Blog, Mint Electronics.
LM317 Power Supply Design. (SOLVED)
« on: January 13, 2012, 11:57:44 pm »
Well I am designing an Lm317 voltage regulator, however I am a bit stuck. I have no idea how much current the lm317 needs to operate, and I cannot find it on the data sheet. I need this to understand what wattage to pick for resistors. I am planning to power this from 12v dc charger that supplies 3A, will I need to place some kind of resistor before the Vin? Or is the 50ohm resistance enough inside the 317?
See attached picture for circuit.
« Last Edit: January 14, 2012, 03:34:41 am by Mint. »
Personal Blog (Not Active Anymore), Mint Electronics:
http://mintelectronics.wordpress.com/
 

Offline vk6hdx

  • Regular Contributor
  • *
  • Posts: 57
  • Country: au
    • vk6hdx - Twitter
Re: LM317 Power Supply Design.
« Reply #1 on: January 14, 2012, 12:20:35 am »
I have no idea how much current the lm317 needs to operate, and I cannot find it on the data sheet.

Hi Mint, are you referring to the quiescent current?  If so this is available on the datasheet.  Otherwise the current required by the 317 @ vin will be proportional to the current drawn @ vout.

No need to use a currently limiting resistor on vin as the 317 has all the internal protection it needs.
 

Offline Mint.Topic starter

  • Frequent Contributor
  • **
  • Posts: 523
  • Country: au
  • Account is inactive now. Thanks everybody!
    • Personal Blog, Mint Electronics.
Re: LM317 Power Supply Design.
« Reply #2 on: January 14, 2012, 12:25:45 am »
I have no idea how much current the lm317 needs to operate, and I cannot find it on the data sheet.

Hi Mint, are you referring to the quiescent current?  If so this is available on the datasheet. Otherwise the current required by the 317 @ vin will be proportional to the current drawn @ vout.

No need to use a currently limiting resistor on vin as the 317 has all the internal protection it needs.

Perfect! Thanks!
Personal Blog (Not Active Anymore), Mint Electronics:
http://mintelectronics.wordpress.com/
 

Offline metalphreak

  • Frequent Contributor
  • **
  • Posts: 815
  • Country: au
  • http://d.av.id.au
    • D.av.id.AU
Re: LM317 Power Supply Design. (SOLVED)
« Reply #3 on: January 14, 2012, 09:51:31 pm »
That is also where you get the value for power dissipated by the regulator. Current in is the same as current out, combined with the voltage drop across the regulator (Vin - Vout), gives you the power dissipated.

P = (Vin - Vout) x I

The greater the different between input and output voltages, the lower the efficiency as the regulator consumes more power.


Share me

Digg  Facebook  SlashDot  Delicious  Technorati  Twitter  Google  Yahoo
Smf