A diode does not half the voltage! It halfs the power. I assume you have 240V. A diode reduces the voltage to 240V*0.707=170V
Surely it will just half-wave rectify and you will still have the peak voltage present - 240*1.414=340V, not 170.
If you stick a capacitor after that what you get depends on the load and value.
Eh, no.
He was speaking of RMS voltage. The RMS voltage of half-wave rectified mains (which is 230V in UK) is 163V. Do the math, it checks out.
AC dropper caps only work when you only have AC currents in your circuit. This is not a trait of a half-wave rectifier.
The capacitance for this is: 1/(2 x pi x 50 x3.2) = just under 1000uF so if I had a 50V 1000uF it would act as a lossless 3.2R resistor to take off my excess 16V. Or course I need a zener across it to make sure it does not go over voltage when the fans start up (it should see on average 32V).
Repeat after me: A capacitor is not a resistor.
There are phase angles involved, something which you clearly haven't taken into account.
Wiring fans in series is a
bad idea. A fan is not a predictable load.
Let's say one of the fans gets a bit of crap into the bearings and gets slightly more load. The speed of the fan will drop, reducing EMF, the overall voltage on that fan will drop, meaning every other fan will get a voltage boost. Do you see the problem?
Simon, hate to break it to you, but you clearly don't have the experience to work on a circuit like this. Just get a pre-made SMPS (something like a 12V Meanwell with a trimpot) and do it safely, or switch the fans with ones rated for mains voltage.