I don't have a workable link. My question is really "How would you write the loop equations?" for a battery in parallel with a resistor.
I would start in the lower left corner and draw the loop in a clockwise rotation. I would go up through the battery and consider that a gain of Vbat. I would continue over to the resistor and see the voltage at the top of the resistor as higher than at the bottom, justifying my clockwise rotation. I would compute the voltage drop as the current I times the resistor R and assign it a negative sign because I am entering at the + terminal.
When I was done I would have +Vbat - (I * R) = 0.
Apparently, the new math is the opposite: Consider the battery as negative and, since the current is entering the resistor at the + terminal, consider that voltage as positive. The equation would be -Vbat + (I * R) = 0
Either way, the equation simplifies to Vbat = I*R -> the voltage in is equal to the current flowing through the resistor times the value of the resistor. Solving for I = Vbat / R.
Like I said, the same answer but the convention seems backwards from what I was taught.
The only reason I bring it up, knowing that the proper application of either approach will yield the same answer, is that my grandson is taking a circuits course next semester and I need to get it right,
https://www.khanacademy.org/science/electrical-engineering/ee-circuit-analysis-topic/circuit-elements/a/ee-sign-convention?modal=1