Does your circuit work if you place the 1N4148 in series with the current driver? This would offer a lot of protection against reverse voltage (like dozens of volts) and you wouldn't be risking frying the diode.
Do you know what kind of reverse voltage/current you will encounter?
Or, is it the case that you need to also trigger on a reverse voltage pulse? In that case, look at Figure 14 of the datasheet ("Basic AC Application") for how to operate with a diode bridge in front of the driver.
Btw, circuit A will not protect the led driver from reverse voltage.
Update: Upon closer inspection of their Figure 14 I'm a little puzzled now. They show this schema:
This will certainly work, but wouldn't also a more traditional use of a full-wave bridge rectifier also work, e.g.:
?