I have an MCU GPIO acting as the control pin to a load switch enable. The load switch enable is active-high, and therefore majority of the time I have the GPIO pulled low on the MCU side, and will enable the GPIO when I want to turn on the rail.
I seem to have omitted a pull-down resistor on this particular rail. I’m a relative beginner, and I understand pull down/up resistors can help a pin always be in a defined state - I’m not so much concerned about this as my device is always on, and the MCU will always be controlling the pin.
However, I’m a bit confused on the current path now that the pull down resistor is gone. Am I at risk of damaging my load switch if I drive the enable pin directly at VDD with no external resistor? How can I figure this out if so?