| Electronics > Beginners |
| RC Question |
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| Yansi:
Just for the sake of it to verify my formula: |
| bostonman:
--- Quote ---p(t) = e-2t/T * Usupply2 / R --- End quote --- I apologize, it looked like you typed p(t) = e-2t/T = Usupply2 / R So I didn't pay much attention to that formula because I thought you were giving me something linear. |
| bostonman:
The curve provides a nice visual. Out of curiosity, should that curve be integrated to give a total amount of power dissipated throughout the entire time constant? |
| DannyTheGhost:
If you integrate power over time you get energy, that's what you need to understand. As were stated above, to get your 'power dissipated' you simply need to get energy stored in capacitor (CU2/2) and divide it by 5*RC (how much time needed to 'fully' charge capacitor) energy/time=power |
| Yansi:
--- Quote from: DannyTheGhost on June 16, 2019, 04:12:27 pm ---If you integrate power over time you get energy, that's what you need to understand. As were stated above, to get your 'power dissipated' you simply need to get energy stored in capacitor (CU2/2) and divide it by 5*RC (how much time needed to 'fully' charge capacitor) energy/time=power --- End quote --- I don't understand your math. You either want POWER, which in this case is changing with time (then look at my exp equation), or you want the TOTAL ENERGY DISSIPATED, which does NOT have anything in common with your time constant, not even anything like 5*Tau. Total energy dissipated is equal the energy stored in the capacitor, which is exactly W = 0.5*C*U2 |
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