Bode plot of opamp integrator

[opampsmoker]

Hi
Why does the LTspice AC simulation give the phase near the f=0 axis as 180degrees for this opamp integrator?
This cannot possibly be right. Surely?

The transfer function is – (1/jwC)/ R,
Which equals     0 + j (1/wCR)
The phase of this is atan {[1/wCR]/0}
..this is atan (infinite) which is n.pi/2, where n = +/- 1,3,5,7,9 etc

This cannot possibly be 180 degrees. Do you agree?

[mag_therm]

It is an inverting integrator. (?)
Phase will go from 180 to 270 at the corner.

I use qucs and it is a bit tricky in graphing phase that goes through the upper/lower limits set by user on the phi graph.
But I think it does it correctly.

[Kleinstein]

Near f = 0  Hz one would see the limited DC gain of the OP and thus a constant gain. So a 180 deg. phase is correct.

[opampsmoker]

Near f = 0  Hz one would see the limited DC gain of the OP and thus a constant gain. So a 180 deg. phase is correct.

Thanks, you mean if it was a ideal opamp then it would be 270 degs near the f=0 axis?

By the way, page 10 of the following has phase near f=0 axis as 90 degrees, not 180 degrees
ti.com application note
https://www.ti.com/lit/an/slva662/slva662.pdf?ts=1607167216358&ref_url=https%253A%252F%252Fwww.google.de%252F