What is the real reason to use a resistor at the base of the BJT transitor?
Beginner to beginner (I assume)....
For the input signal on the base you don't need to supply very much current. Milliamps, to work out just how many you need the datasheet, the "gain" across the collector/emitter and the current you want to flow across them in your circuit. Divide the current you want by the gain, apply that to the base. You can work out the resistor you need using Ohm's law.
If you don't put a resistor (as I found out) the Base->Emitter current will try and power the circuit beyond the trannie and the trannie will get hot.
The "pull down" I am referring to however is what happens to the Base of the transistor when you disconnect the signal to the base. With the base disconnected the current/voltage on the base is "undetermined" and subject to interference/RF/noise. By connecting the base to GND/0V you know that zero current will flow into the transistor. It should be a pretty high value resistor (1M sort of thing) so that when the signal is connected you aren't "throwing away" a load of current to ground.
With a pull down in place, if your base current needs to be precise, you will need to factor the pull down into the equation to get your base current.
Some of that will be wrong or non-pedantic, so I'd be grateful for corrections.
