Electronics > Beginners
Secondary current rating of a center tap transformer?
(1/5) > >>
techguru:
Hi to all,

I have center tap transformer of secondary rating 24V-0-24V @ 5 ampere.I use bridge rectifier for constructing power supply which will power opamp circuits. what is the current i could draw form each line?

my thought is my peak voltage after filtering is 33.94V(24 square root of 2). so i could take 33.94V and 5 ampere, so i could total DC power is nearly 170 W with out regulation circuit. My conclusion is that i could take 170W from positive voltage line  and another 170W from negative line with respect to ground.
 
correct me if i am wrong???
iMo:
My understanding is you have the bridge wired to 24-24 leads and the 0 lead is the ground.
I think your peak voltage will be 68V (measured on the capacitor wired to the Greatz' output with no load), subtract few volts lost on the diodes, based on the filtering capacitor you get a ripple (ie with a 10mF capacitor and 5A loads it will be 10Vpp ripple around 53V mid), the peak diode's current will be about 20A, and you can draw 5A from each line.
mariush:
It's 48v at 5A = 240VA

If you convert to DC using a regular bridge rectifier, then the current will be ~ 0.62 x 240 = 150W  but naturally, the peak DC voltage would be higher.

techguru:
I want the power that could be taken form +ve line and -ve line with respect to ground?. my transformer is 24V-0-24V @ 5 ampere..
iMo:
Yes, as I wrote above.. You may use 1 capacitor or 2 capacitors..
You will get aprox 68/2 -> +34V and -34V with no load, and aprox +24 and -24V with 5A load. Mind the ripple on each rail - it depends on the capacitor's value, with (for example) 10000uF it will be about 5Vpp @5A on + and - rail.
Navigation
Message Index
Next page
There was an error while thanking
Thanking...

Go to full version
Powered by SMFPacks Advanced Attachments Uploader Mod