I'm a bit concerned about having the 2.5V from the charger ISET1 pin going into the high 1.8V digital output. How do you think that will affect the circuit?
Internal protection diodes will conduct. Series resistance you will have to add will protect from damage. But this affects voltage levels: with diode from the pin to Vdd, pin is clamped to approx. Vdd+0.3V = 2.1V.
Equivalent circuit is two voltage sources V1 and V2 connected together by R. V2 is always 2.5V.
Assuming Rpu = 13k and Ppd = 13k (somehow I remember this is the case with nRF52, check the datasheet of course), and setting Rext = 13k as well
Pin driven LO: V1 = 0V, R = 13k
Pin hi-Z with PD enabled: V1 = 0V, R = 26k
Pin hi-Z:, with or without PU enabled: V1 = 2.1V, R = 13k (protection diode conducts)
Pin driven HI: V1 = 1.8V, R = 13k
Of course, re-check my thinking.