I put some caps before the lm39302 to ensure no big spikes happen, 3x 10uf as i remember. plus, 0.5v isn't much to cause such heat. I didn't do any measurements to see actual stuff happening.
If you have a +0.5v input to a low dropout regulator, it's output transistor is basically almost nailed 'ON'. Now in the 'AOZ1284' datasheet, even with it's recommended output caps, it's output dips by 0.4v when the load switches by 2 amps. To filter this through a lm39302 you would want +1v above your output voltage instead of 0.5v. If you had something like a 47000uf cap at the regulator input, then you probably could get away with 0.6v above your output voltage. Just adding a capacitance multiplier inbetween means the drop there will just make more heat for it's theoretical minimum optimum drop of now 0.7v for the transistor + 0.5v drop for filtering 'AOZ1284's 0.4v drop + ripple noise meaning 1.2v drop. Now you have 1.2v drop on cap multiplier + 0.5v optimum drop on linear regulator. That's still a total 1.7v drop in heat being injected into your PCB. We can do better and save money.
The transistor derating you are reading is the transistor not even mounted on a PCB, complete open air. Even a PCB alone will drain away heat.
you mean junction-to-ambient? I keep reading people say that even putting some copper area for dissipation will not help or won't make a difference.
Yes, if the PCB has no cooling or air flow, the heat up will happen, it will just take a little longer as the PCB itself warms up. The same is true of a heat sink. Still, you don't need so much as each transistor will have a ~1.5v drop, 1.2 amps load each meaning a total of 3.6 watts to radiate away from those 2 transistors. You can shave the 'AOZ1284' down to 1.1v above the desired output voltage, 2.7 watts of heat for both transistors, but, I would test and trim these.
Just get the cheapest adjustable linear 100ma regulators (LM317 in SMD) which can go to at least 18v input and down to 3.3v out.
You will use the 100ma regulator's output to feed the base of the MJD44H11T4G, multiplying that supplied current by the transistor's current gain curve which could drive ~ 5amps, however, the sweet spot is at the 3amp mark where the transistor's gain is clearly above 100.
you want to use lm317 for its stable output? how will this affect the final 3.3v and 5v without a linear post-regulator?
The LM317 + MJD44H11 creates an adjustable 5 amp linear regulator. You don't need anything else. And because of the way we are wiring it, you wont even need more than a 10uf cap on the output.
The 100 ohm + 10uf cap feeding the Vin input of the LM317 means no high frequency ripple reaches the regulator's reference or GND pin.
The regulator output pin has a parallel 1uf cap and 1K resistor to GND to prevent output oscillation and guarantee a minimum load.
That output through a series 10 ohm resistor to prevent transistor oscillation feeds the base of the MJD44H11.
The emitter output of the MJD44H11 goes through a feedback resistor to the ADJ pin on the LM317 and that pin has the second feedback resistor going to your GND reference. Just like in the LM317 data sheet, except the R1 is taken from the transistor emitter, not the regulator's Vout.
On the MJD44H11 emitter, also add a 10uf cap to GND and a 220ohm resistor 1/4watt to GND to make sure the transistor stays on at 0 load.
This is a linear regulator where the output stage is buffered 200 fold at 2 amps, 100 fold at 3 amps according to the transistor datasheet's DC current gain chart.
The reason this setup wont transmit any noise from the 'AOZ1284' to your outputs is that the entire regulator circuit is running at ~12v, coming from a 100 ohm - 10uf RC filter. Meaning that the regulator circuitry and reference only needs to deal with and filter out frequencies below 1Khz at the Vin pin, it wont have to deal with 10Khz spikes & 1-2Mhz RF which typically would go right through it. With 100uf on the LM317 V+ pin instead of 10uf, now the regulator will only have to deal with ripple noise below the ~100Hz range, a frequency range it was well designed for.
The sensitive regulator circuitry never sees all the RF EMI on the MJD44H11 collector pin coming from the 'AOZ1284' output & source switching supply so long as you carefully lay out your PCB while the 85MHz MJD44H11, at low currents like 0.5 amps will still reject much of frequencies above 10Mhz. I doubt 2Mhz could be seen on the output unless it being picked up and amplified by a looping GND on the PCB.
This eliminates those pesky additional linear regulators and makes less heat and would probably deliver a much cleaner output.