It would look line a <0.0005 ohm short to GND @ above 500KHz thanks to the 10uF MLCC cap in parallel.

how do you know these exact numbers? I know the RC filter removes ripple and noise to some degree but I cannot know details such as its performance at a certain frequency or so.

This isn't too difficult if you look at the capacitor chart I posted on the previous page:

For simplicity sake, we will use the 470uf and 22uF MLCC caps. IE, 1/2 the 1000uf cap and 2x 10uf caps in parallel.

The chart labels these as separate impedances, not both components in parallel which would be similar to adding 2 resistors in parallel. I assume you know how to add 2 different parallel resistors together.

Let's concentrate on just the 22nF cap, the cyan-blue line on the left chart.

At 100Hz, you can see it is 100ohms. This means if you place this cap after a 100ohm resistor to GND, feeding a 1v 100hz sine wave signal into the 100ohm resistor means on the other side, 100ohm -> cap which = 100ohm to GND @ 100Hz, your 1v 100Hz signal will now be 0.5v.

Now say we feed a 10Khz 1v sine wave into the 100ohm resistor, well now, the cap at 10Khz looks like a 1ohm resistor to GND.

The formula here is the same voltage attenuation formula, 1ohm/(100ohm + 1ohm)= 0.0099v 10Khz sine wave at the output of the resistor, or we can call that 0.01v.

Do the same for 1Mhz and it's 0.001ohm/(100ohm+0.001ohm) = 0.0000099999, or we can call this 0.00001, or 10000:1 attenuation. Assuming I didn't get my decimal places incorrect.

For the purple 470uf trace, a 1000uf cap would run a little lower in resistance in the middle, but be ~half the resistance down at the 100hz location.

As for the regulator and opamp, there is a specification in their datasheet called PSRR, or power-supply-rejection-ratio or sometimes called 'Ripple Rejection'. This tells you how much the device attenuates down the input signal at a given frequency. The on-seminconductor MC78L05 datasheet says it's PSRR when powered at 10v driving 40ma is 49db @ 120hz. (Not the best one, but ok.) So going to this site, I put -49db into the calculator:

http://www.sengpielaudio.com/calculator-db.htmAnd get: 0.00354.

Looking at an 100ohm to 1000uf cap at 100hz, it's a little less than 0.01, multiplied by that regulator's -49db PSRR 0.00354 gives you 0.0000354 of your original 100hz signal before all the in place filters to after the regulator.

If you old circuit generated a 1v 100hz hum, after all this, that 100hz hum would be ~0.00004v.

So, a 0.1v 100Hz hum would become ~0.000004v.