It will probably blow the MOSFET or at least drastically shorten its life because it exceeds the maximum rated gate-source voltage of 8V.
To get round this, you need a potential divider to reduce the gate voltage. If you add another resistor with the same value as R1 (call it R2), it will half the gate voltage, so give you 8V when the input voltage is 16V but you don't want to go anywhere near the maximum rated voltage, so set R1 to 100k and R2 to a slightly lower value say 82k.
Is this really necessary? Can't you find a normally closed switch rated to over 600mA at 16V?
No, I dont find any with a small size.
so you say something like:

8V its the max voltage, but what could be the minimun safe value?
Lowering the voltage, it lower the current flow I guess right?
Appart from the voltage, how do you choose how many current will flow through the Gate? The minimun I could?
Can you share a better component to do this?