So the higher the frequency, the more demanding everything has to be solid. Why is that though? This is the answer I found online:
Generally, yes, everything involved in the circuit becomes more significant. Every conductor has series inductance, series resistance and parallel capacitance to every other conductor in the vicinity, including you. Straight wire has about 10 nH inductance per cm length or 1nH/mm. To put that into perspective, the inductors recommended for this chip are from 470 nH to 1000nH. So a total of 1 inch extra distance that current has to travel around the ON or OFF current loops is already an extra 10% of the component inductance that does not appear on the schematic and affect the available duty cycle and consequently, max load that can be supported. These loops through the inductor or the switches may carry several amps of current. An extra 1 inch of thin copper path can have a voltage drop of 20-50 mV and be an appreciable fraction of the feedback voltage. This can drive the stability of the regulator nuts for no apparent reason.
The push-in proto boards are notorious for making long paths in circuits built on them with relatively high contact impedances between wires and the sheet metal rails that everything connects to. They are terrible for high-frequency work.
If you don't want to go to the trouble of a manufactured pcb then you might construct a proto over a ground plane by using copper-clad and using Manhattan-style or dead-bug construction. This style can work up to 100 MHz. If you dont know what this is just google "dead-bug construction". Also, for the sake of low parasitic inductance/resistance construction, use only SMT parts, not TH with leads. In fact, it might be the best option to first build a dead-bug style version over ground plane then go for the pcb once you know it can work
So is it due to noise caused by the above reason?
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So what's the worse that can happen? You mentioned smoke a lot. Is it the inductor or the IC causing the smoke usually? Worse case scenario, does the component just destroy itself and the circuit stops working or can it actually burst into flames and be a fire hazard? I just need to know for liability purposes.
It seems like designing a boost converter, even with an IC, is a lot harder than I expected. I guess even if I work with a professor and make a custom PCB, there will still be a lot of troubleshooting before the device can be "market ready" right?
Lots of questions, but I need to know since I might want to eventually commercialize an application that requires this. If it turns out to be too risky I might just use more batteries instead...
Thanks for your advice.
The push in proto board itself doesn't cause noise, so much, as it introduces a lot of parasitic components which become so much more important at high frequencies and high currents.
As for smoke...
So many people, including engineers very experienced in other circuit areas have smoked SMPS regulators on their first (or 6th try). I know, I did! Follow the heavy current paths. The ON current path is the input cap, inductor, lo-side switch, and back to input cap. If the controller chip fails for any reason and leaves the switch on too long then both the switch and the inductor are toast. The on-going current will be supplied by a source power supply that will be oh so happy to supply all the circuit wants through the inductor and the switch. That wipes out both the inductor and the chip. I hope you have extras.
Actual fire is not likely but a puff of actual smoke can occur.
If all of this seems alarmist, it's not. But good results can happen if you don't get cocky and follow the chips datasheet recommendations as well as possible, using high-quality physically small parts (inductors with sufficient saturation current and low ESR, capacitors with low ESR, non-inductive resistors) and a small, tightly collected layout with optimally-short current paths.