Author Topic: Transfer function  (Read 582 times)

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Offline m.jayidTopic starter

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Transfer function
« on: May 05, 2021, 11:23:34 pm »
Hi everybody.
I am a beginner in electronics.
Can you please hep me fin the transfer function (the relation between Vout and Vin), its gain, the cutoff frequency of this amplifier and what is it good for .
Thank you very much.
 

Offline ledtester

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Re: Transfer function
« Reply #1 on: May 05, 2021, 11:53:49 pm »
This is the same circuit you asked about in this post:

https://www.eevblog.com/forum/projects/current-sensor/msg3551696/#msg3551696
 

Offline m.jayidTopic starter

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Re: Transfer function
« Reply #2 on: May 06, 2021, 12:07:52 am »
Now, I just want the transfer function.Since I did not get yet.
 

Offline JohnnyMalaria

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Re: Transfer function
« Reply #3 on: May 06, 2021, 12:10:49 am »
 

Offline ataradov

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Re: Transfer function
« Reply #4 on: May 06, 2021, 12:32:30 am »
This sounds like you want us to do your homework. This is not how it works.
Alex
 

Offline CatalinaWOW

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Re: Transfer function
« Reply #5 on: May 06, 2021, 12:50:19 am »
There are two general ways to get the answers you are looking for.

The first, as suggested above is to enter it into spice.  As a hobbiest or a student this is a skill you should develop if you want understand or use transfer functions.

The second way is by hand, and is the only way to get a closed form answer for the transfer function, which is probably what a student is being asked to do.  I will give you a couple of hints.  It is a non-inverting op amp stage.  With some additional shaping.  Looking at your class notes or the internet you should be able to take it from there.  Remember the rules for connecting components in series and parallel and remember that these are complex impedances, not simple resistances.
 


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