| Electronics > Beginners |
| Turn-off of constant current source using the reference voltage |
| (1/1) |
| brumbarchris:
Hi all, I am currently studying this constant current source with opamp and P channel MOSFET. there is something I do not understand and that I would like to ask. The way I see it, the opamp will alwas drive the gate of the MOSFET so as to keep the negative input to the same voltage as the positive input. I would therefore expect that if I increase the reference voltage to 5V, the gate voltage will rise high enough to completely turn OFF the mosfet and to ensure the negative input also reaches 5V. I do not see this behaviour in simulation, though. If I rise the VREF voltage, the VGAT only increase so much, and the Vin voltage is clamped somewhere at 4.15V. So I guess the question is: why doesn't the opamp block the MOSFET when VREF=5V? |
| awallin:
try a higher supply-voltage for the op-amp. the output will go more or less close to the positive supply rail but not beyond.. |
| brumbarchris:
My intended goal was to turn off the mosfet by connecting the positive input of the opamp to the supply voltage. And I only have/want a single supply voltage in this circuit. Cristian |
| MarkF:
The LT1006 opamp output can only go to (V+) - 1.2V. Which will probably not completely turn off the MOSFET. Are you just trying to switch the output on/off or control the current? For just switching, this circuit for a solar panel charger may help. |
| brumbarchris:
Yep, it was the limited output capability of the opamp to swing to the upper rail. Changing the opamp solved it, thanks. I now ran in different problems, but I will post in the Projects and Technical stuff forum section, as it is not "beginners" stuff. Regards, Cristian |
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