EEVblog® Electronics Community Forum
Electronics => Beginners => Topic started by: selim on November 03, 2022, 08:59:07 pm
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In addition to question, what would we see on the monitor?[attachimg=1]
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Did you forget to write " Kindly give me an answer ASAP, my homework is due tomorrow morning" ?
:-DD
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The output depends on the frequency of the signal generator.
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The output depends on the frequency of the signal generator.
A smart student will not give a number as an answer, but a formula to calculate the value depending of the frequency, a very smart student will add the probe impedance in the equation and a young genius will use Wolfram Alpha :-DD
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I think the question is attempting to discover if the student has a good grounding in using an oscilloscope. :)
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The implication of the test question is that it won't work properly. If you assume that the triangle under the 10V source and the black clip of the oscilloscope are common grounds, then the capacitor will be shorted and you'll have the full 10V, in phase, across R1. And that's what you see on the scope, more or less, again assuming that you have a high-impedance input on the scope and perhaps a 10X probe. But IMO, none of those assumptions is really justified without explicitly stating them.
For a high-impedance scope/probe and no common ground, you see an amplitude less than 10V and out of phase (leading) the source voltage, varying with frequency. But you can't answer that question precisely without knowing the frequency of the AC source, so that's your clue that any such answer is not what the question is looking for.
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Noise. There is a 1px gap between the grounding clip and the circuit. ;)
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Did you forget to write " Kindly give me an answer ASAP, my homework is due tomorrow morning" ?
:-DD
I'm still waiting for the day when we get exactly the same question from half a dozen people on same evening. ;D
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The output depends on the frequency of the signal generator.
It will not.
Watch "How to blow up your oscilloscope" by David L. Jones.
edit
I mean, the amplitude doesn't ::) |O
Other aspects may still vary :-DD
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The output depends on the frequency of the signal generator.
A smart student will not give a number as an answer, but a formula to calculate the value depending of the frequency, a very smart student will add the probe impedance in the equation and a young genius will use Wolfram Alpha :-DD
And a practical engineering student will watch my video:
https://www.youtube.com/watch?v=xaELqAo4kkQ&t=641s (https://www.youtube.com/watch?v=xaELqAo4kkQ&t=641s)
BUT the schematic does not show a earth symbol, only a circuit ground symbol, so it could be floating.
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In addition to question, what would we see on the monitor? (Attachment Link)
As per the rules for this section, please show what work you have done already to try and solve the problem.
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This reminds me of those math problems that are always showing up on YouTube. They write a math expression but do not explain which, of several, rules of interpreting the manner of writing that expression. So, no matter what answer you give, someone will say you are wrong.
I hate those math problems and I could grow to hate electronic questions like this.
I say, if you want to know what you will see, connect the scope to the circuit and you will be enlightened. And if someone disagrees with your observation, please be kind.