Ah! I totally missed the "COM" pins
I think I understand it a little better now.
So the MUX chip (74HC4052 in this case) basically works as a two-pole, 4-way switch, like this?
Yes, it is a 4 position switch with 2 control input pins.
Remember, the device operates exactly like a mechanical 4:1 switch. (Actually 5:1 if you count the EE as a switch position with nothing connected...)
The signals travel in both directions just like a mechanical switch.
You may have unconnected IO pins just like a mechanical switch.
The 2 most important points is that:
1. For the 74HC4052, the electricity on any of the switches IO pins cannot go below the Vee voltage, or go above the VCC voltage, otherwise, you will blow the chip.
2. The quality of the contacts of these switches are their on resistance, in the case of the 74HC4052, it is 60ohms. It is like your switch is a really long resistive wire in circuit.
Wow! Hugely better than the 60 Ohms of the 74HC4052. Still, will there be noticeable signal degradation with 60 Ohms?
Remember, for the analog video mode, the monitor's analog input has a resistor of 75ohm to GND.
This means, if your analog switch when on has a 75 ohm series resistance, then the signal the monitor would get would be half bright because of the monitor's 75ohm load. (This is an example, there is actually already another 75ohm series resistor in your Atari ST's video DAC output as well, so the loss is actually less...) Since the 74HC4052 has a 60ohm series resistance, the final picture would be a little brighter than 50%. If the analog switch has a perfect 0 ohm short when on, then the monitor's brightness would be perfect.
So, for my recommended TI part#, TMUX1104, it has a <2ohm short when turned on if you powered it with 5v. At 2 ohm, you will not see the ~1.3% drop in overall contrast (Assuming the Atari ST analog output has the standard 75ohm series resistor) in the image for analog picture modes (digital would have 0 effect). If you powered the TMUX1104 at the absolute max 6v, it will approach ~1 ohm.
This is my PCB recommendation for a hand-wired switch-box solution:
Make a tiny 10x10cm 2 layer board with 1x TMUX1104, 1 or 2 decoupling caps, and a common through-hole connector on 1 side with GND, 5v, S0, S1, ENA. All of your 8 PCBs for the 8 poles will have these ports all wired in parallel. Use something like long gold standoff pins or thick single strand copper wire through all 5 pins of the 8 boards in parallel. Actually, add a second GND pin.
On the other side of the PCB, make a 4 pin connector, COMMON (IE: Switch wiper), Position 1, Position 2, Position 3, Position 4. Space these guys out for wiring. Actually, add 2 additional GND pins so you may solder the 8 boards with the standoffs on both sides just to make it more sturdy.
10cmX10cm boards for first time buyers from a Chinese costs around 5$ for 10pcs delivery next day.
It is a cheap as you will get. (You may be able to fit 2 or 4 TMUX1104 on a 10x10cm pcb.)
You will need to supply the MUXs with 5v. A 78L05 and 2 caps and 9-24v adapter will do, or a quality USB 5v supply.
Yes, I think I understand the basic concept a little better now. Do other MUX chips work much in the same way?
For analog capable MUXs, yes they all work in a similar fashion.
For digital MUXs, they only discern between digital high and digital low, plus, they only transfer the signal in 1 direction. Most digital MUXs go from the multiple input channels to a 1 common output.