I am feeding a 1kHz sine wave with a 2Vpp amplitude
What did you mean "2Vpp" amplitude?
Vpp = means peak-to-peak voltage
Vpk = means amplitude voltage
Vrms = means rms voltage
Vpp = 2 * Vpk
Vpk = Vpp / 2
for sine wave:
Vpk = Vrms * sqrt(2)
As I understand, you're used Vpp by mistake and actually you're talking about Vpk which is a half of Vpp. Isn't it?
But there is also unclear if you're talking about loaded output or HiZ.
Usually Chinese sig gen show you HiZ voltage. It means voltage for the case, when you don't load sig gen output with a load.
If you connect something to sig gen, include oscilloscope or voltmeter, the actual voltage will be different. Because voltage will depends on the load impedance. For example oscilloscope 1:10 probe usually has 10 MOhms impedance. And oscilloscope 1:1 probe usually has 1 MOhm impedance.
Since sig gen has 50 Ohm impedance and your load has R impedance, it turns into voltage divider
U = U
HiZ * R / (50 + R)
If you load sig gen with 50 Ohm it turns into:
U = U
HiZ * 50 / (50 + 50) = U
HiZ / 2
When I view the output of the sig gen with the approx 50 ohm resistor across the signal and ground pins, the scope will only see a sine wave of about 1.50Vpp at the transformer "input" (secondary coil). So that in theory I should get 15.95Vpp approximately at the output (primary coil), which is closer to the 16.2Vpp which the scope shows in real.
this is incorrect measurement. Remove any 50 Ohm resistor across the signal and use high impedance probe (at least 1:10) to measure amplitude on the transformer input.
Why does the signal from the sig gen have such a significant difference from the expected 2Vpp output, when terminated with the approx 50 Ohms?
You're needs to look at transformer as impedance transformation device.
Also you're needs to take into account source and load impedance. This is very important!
Because result will depends on both - source and load impedance and impedance transformation ratio of the transformer.
Transformer impedance ratio is a square of turns/voltage ratio.
Since you're mentioned turns/voltage ratio is 10.6345, then:
impedance_ratio = 10.6345 ^ 2 = 113
But actual impedance ratio will depends on the transformer properties which depends on the coils coupling, core properties and frequency.
Let's assume that impedance_ratio at 1 kHz is 113 and signal generator output is 50 Ohm, then you're needs to load transformer with:
Zload = Zsrc * impedance_ratio = 50 * 113 = 5650 Ohm
In such case you will get max efficiency and output voltage will be about 10.6345 higher than input.
If you put transformer output to a different load, then transformer input impedance will be different.
It will leads to sig gen impedance mismatch and as result, worse efficiency and different voltages on the input and output coils.