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Vout on an HPF with a Simulated Inductor
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eev_carl:
Hi,

I built the attached HPF circuit.  It's Figure 2 from this PDF: http://www.ti.com/lit/an/slyt134/slyt134.pdf  .

I have my scope set to logarithmically sweep a range of frequencies and am creating a Bode plot.  When I connect the scope to the output of the lower op amp (NOT Vout as listed in the schematic), I get the attached scope image which looks perfect to me.  However, if I scope Vout as specified in the schematic, I get something (not attached) that looks more like a low pass filter.

I was wondering if someone could help me reconcile what I'm seeing on my scope with the schematic.

Thanks in advance,
Carl


eev_carl:
Here is a picture of my scope where I put the probe at Vout as listed in the diagram.  (At the output of the first/top op amp.)

These are the values that I'm using


* R1 = 10k
* RS = 50k
* C1 = 0.047uF
* R5 = 10k
Could the schematic and PDF possibly be wrong in their listing of Vout?

Thanks,
Carl
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