hI hUBI, yES IT IS JUST AN output pin as of 3.3 V which I am going to use in voltage divider as an output voltage. So what could be the current for 3.3V? Like that I would be able to know the value of R2 in voltage divider.
I am not quite sure what you mean by current for 3.3V.
You want to divide the voltage so that it is in the measurement range of the ADC. If your maximum input voltage is 6V and the maximum voltage your ADC can read is 3.3V, then dividing by half seems like a good choice. So you can use the same resistor value for R1 and R2.
There will be some current through the voltage divider, which will drain the battery. To minimize the current, you want to use large resistor values. But there are limits to that, I doubt you could get an accurate reading if you picked 1 MΩ for the resistors. If you put a capacitor parallel to R2, you can use higher resistance, but you have to wait for the capacitor to charge, i.e., you cannot read the battery voltage as often. If you want to read the voltage every second, try 1 MΩ for the resistors and 0.1µF for the capacitor. This will draw 3µA at 6V battery voltage. If you can wait 10 seconds between readings, you could try 10 MΩ and reduce the current draw by a factor of ten. Just experiment a little to find out what works for you.