Ah, tggzzz has alternative facts…
So what then is the characteristic impedance of your ‘very lossy transmission line’ in your probe cables? 1 Mohm??
The central conductor's resistance is around 300ohms/m.
Don't believe me, cut open a probe and measure it with a multimeter.
Basically your understanding is based on, to repeat your phrase, alternative facts.
Don't believe me, but do believe Tek, p14 of http://www.davmar.org/TE/TekConcepts/TekProbeCircuits.pdf
This a good reference for other classes of probes, too.
Yes, great Tek manual from the old days. The resistance of the coax center wire is there in decent probes and helps in certain scenarios. But it cannot prevent the reflections at the two impedance jumps (the two ends) in the transmission line. Assuming the coax is still 50 ohms characteristic impedance (or maybe it's 20 or maybe 200 ohms or whatever - but it will not be a Z of kohms or Mohms, and the resistance of the center wire is not to be confused with characteristic impedance!), then at both ends, seen from a wave travelling within the cable, a wave that's about to hit the impedance jump, the refection back is still huge. Reflection coefficient is (Zload-Zcable)/(Zload+Zcable). Only way to get that to zero is when Zcable = Zload. There are no cables with a Z of 1 Mohm...
Assuming A is the probe and B is the scope's BNC, 1 Mohm input, at say one or two meters displaced from A, one cannot claim that the signal goes beautifully, unchanged, from A to B, with nothing bouncing back into the same cable at B. What bounced at B will propagate back to A (if the wire resistance didn't kill it on the way out, then why would it kill it on the way back?), and there again an impedance jump, so again a reflection back into the cable. Plain physics.
Only matched impedance at B would do the trick. The Finnish DIY probe does approach that. The Tek Z0 probes with 50 ohms cables into a 50 ohms scope input do that. But no probe into a 1 Mohm input can do that, no matter how thin you make the center wire in the coax cable.