| Electronics > Beginners |
| Why binary is represented by two bits 0 and 1 and not three bits? |
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| tggzzz:
--- Quote from: wraper on October 30, 2019, 04:48:42 pm ---CMOS consumes barely any current when staying in stable state, current flow happens only during changing state. --- End quote --- No longer true in the latest semiconductor processes. Reducing static leakage currents is a hot topic. |
| wraper:
--- Quote from: tggzzz on October 30, 2019, 05:00:27 pm --- --- Quote from: wraper on October 30, 2019, 04:48:42 pm ---CMOS consumes barely any current when staying in stable state, current flow happens only during changing state. --- End quote --- No longer true in the latest semiconductor processes. Reducing static leakage currents is a hot topic. --- End quote --- There is always some leakage. But calling it "no longer true" is nonsense. That leakage is somewhere in femto-picoamps range per single transistor. |
| tggzzz:
--- Quote from: wraper on October 30, 2019, 05:50:22 pm --- --- Quote from: tggzzz on October 30, 2019, 05:00:27 pm --- --- Quote from: wraper on October 30, 2019, 04:48:42 pm ---CMOS consumes barely any current when staying in stable state, current flow happens only during changing state. --- End quote --- No longer true in the latest semiconductor processes. Reducing static leakage currents is a hot topic. --- End quote --- There is always some leakage. But calling it "no longer true" is nonsense. That leakage is somewhere in femto-picoamps range per single transistor. --- End quote --- Then multiply that by the number of transistors :) The figures I've seen are that the leakage power dissipation can be 30% of the total power dissipation. That will, of course, be dependent on the specific process. |
| Mr. Scram:
--- Quote from: srce on October 25, 2019, 09:27:49 am ---Trying thinking how you would create any sort of logic gate or arithmetic circuit that isn't based on binary. There's not a benefit to doing so. --- End quote --- Ternary computers can apparently be faster or more efficient in both energy consumption and transistor count. We just ended up using binary but it's not the only valid solution. |
| wraper:
--- Quote from: tggzzz on October 30, 2019, 06:35:16 pm ---Then multiply that by the number of transistors :) The figures I've seen are that the leakage power dissipation can be 30% of the total power dissipation. That will, of course, be dependent on the specific process. --- End quote --- Then make it into microamps to make intermediate levels and multiply by transistor count. 30% on leakage for modern CPU in completely unreal. Unless you mean when it runs at 5% of it's maximum clock speed. |
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