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Why does inc R of a RL circuit increase dVL/dt. Here I have circuits and details
jmw:
--- Quote from: renzoms on January 02, 2020, 03:32:38 am ---The voltage across the inductor rose to the voltage supply because the voltage across the voltage supply V, provoked the self-induced emf and voltage drop of the inductor, by the potential difference between the voltage across the voltage source and the resistor and the inductor.
--- End quote ---
Simpler explanation: by assumption, the initial condition current is 0 at t=0. By Ohm's law, no current means no voltage across the resistor. By KVL, the sum of voltage changes around a loop is zero. The entire supply voltage must therefore appear across the inductor.
rstofer:
--- Quote from: renzoms on January 02, 2020, 01:10:40 am ---I'm going to restudy inductors using my book from the library and the help on the internet.
--- End quote ---
Khan Academy Electrical Engineering videos or some of the better Internet sites.
This is a pretty simple explanation:
When you get to circuits with capacitance and inductance, the math starts to pick up the pace.
Here's another explanation
https://www.allaboutcircuits.com/textbook/direct-current/chpt-15/inductors-and-calculus/
And here's a page about the low level calculus that goes into the study of capacitance and inductance. This is a really good explanation of differentiation and integration and, more important, how they are the inverse of each other. Question 8, for example. This circuit would be a great project for LTspice. Just reveal the answer to question 8 and I think you will see a sample of I haven't tried it yet. The first stage is integration and the second is also integration and the output is a sine wave. <== Fixed
https://www.allaboutcircuits.com/worksheets/calculus-for-electric-circuits/
https://www.electronics-tutorials.ws/rc/rc-integrator.html
StillTrying:
The higher voltage limited to 100mA with a higher resistance always wins, there's not a lot of interesting happening. :(
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