Author Topic: [Solved] What's the Q of this circuit?  (Read 2467 times)

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Offline SoftwareSamuraiTopic starter

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[Solved] What's the Q of this circuit?
« on: November 10, 2011, 03:49:25 pm »
While tying to learn more about bandpass filters, I stumbled across this circuit (see pic). Does anyone know how to calculate the Q of this filter?

I know that the addition of the Rload changes the Q, but I'm not sure how to factor both R1 and Rload into the math.
« Last Edit: November 10, 2011, 09:15:49 pm by SoftwareSamurai »
 

Offline Rufus

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Re: What's the Q of this circuit?
« Reply #1 on: November 10, 2011, 04:11:46 pm »
V1 has zero impedance. If you replace V1 with a line it becomes obvious that R1 and Rload are in parallel.
 

Offline jimmc

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Re: What's the Q of this circuit?
« Reply #2 on: November 10, 2011, 07:44:04 pm »
The resonant frequency of L1 & C1 is 159.15Hz at this frequency the reactance (X) of either is 100 Ohm.
As  Rufus has said RS and RL appear in parallel so their combined resistance (R)  is 333.3 Ohm.

Calculate Q as R/X = 3.333

Jim
 

Offline SoftwareSamuraiTopic starter

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Re: What's the Q of this circuit?
« Reply #3 on: November 10, 2011, 09:15:23 pm »
Thanks Rufus. I hadn't thought of V1 with zero impedance. I think that's what I was missing.

Thanks Jim. I thought that Q = R/X, but I wasn't calculating R correctly which made me think that I had the wrong formula for Q.
 


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