Is V2 the PULSE and I1 a true ideal DC current source?
You don't need to put DC voltage in series with a PULSE, though you can and it doesn't hurt anything. You can set the ON and OFF voltages to arbitrary levels, including a DC bias, so it's redundant.
What hurts is, the voltage sources DO NOT MATTER, because when SPICE says "constant current", it means constant. You can put the ass end of the current source to any other node connected by voltage sources, and it makes no difference. Doesn't matter if the voltage across the current source is positive or negative, large or small, current is current.
So, all that you're seeing is a capacitor charging, into a diode-strapped MOSFET (not really, but sort of), into a load resistor, basically. It's not at all representative of a real circuit, and isn't showing you what you want it to.
Remember, SPICE doesn't know what your intent is. (Silly and obvious, but also easily forgotten!) It's just ideal models slapped together. It's entirely your responsibility to make a model that's realistic. Usually, you should be experienced enough to
already know what's going to happen before you even hit 'simulate', which makes it somewhat redundant, but this should give you some perspective: unless you're doing something really "out there", you never use SPICE to determine functional performance ("does it do what I think it should", let alone "I don't know what to think"!), only to tweak the parameters and optimize the circuit to what you need.
Which... doesn't help you any, I know, because that's like saying "you're dumb, give up and read a book", and you're just trying to figure things out. Just be very weary that, if you're trying to learn based on what SPICE gives you... it's only as good as what you're putting into it. Nothing written in SPICE is absolute, definitely not if you're unsure about your model.
(Also... Comic Sans? Reeeeally?...

)
Philosophy aside, I think what you wanted to be going for is, a voltage source (PULSE alone, or PULSE plus DC -- or whatever, any voltage source combination is valid) with a series resistor, corresponding to either the short circuit capacity of the power source you're looking to model, or to the rated current at some voltage drop. Two examples: a 50V 2A (nominal) supply might drop to 45V at full load, in other words, a (50 - 45) = 5V drop, which looks like 5V/2A = 2.5 ohms. (Evidently, the short circuit current would be 50V / 2.5 ohm = 20A.) Another example, maybe you know your supply's short circuit current is 50A, in which case 50V/50A = 1 ohm. This is a Thevenin voltage source.
You can also do it by using a current source (PULSE, DC or whatever, any combination in parallel) in parallel with the same resistor. This is a Norton current source. The two are related by having the same resistor (one series, the other parallel), and I = V/R relating the two sources. Don't mind that the current source appears to be delivering short-circuit power into its resistor: that's virtual watts, you're just using that for its behavior at the terminals.
Tim