I would guess there is a largish capacitor there holding a power rail at some voltage, and the brownout circuitry is keeping the microcontroller in reset, so the outputs are high impedance, allowing the stored charge on the LCD segments to stay in the state they are in. Allow the circuit to stay unpowered for around 5 minutes, and see if the display slowly goes back to translucent, as the stored charge decays odd of those high capacitance planes on the LCD glass.
Also consider that Australia is a few hours ahead of the world, and Dave is kind of famous at this time of year to come out with some really outrageous and quite true items, though they are not always as they seem, but the physics are always true to the experimental world, and most established theories, even if they at first glance do not appear to be so.