Let's say you are able to sneak an articulated arm or similar into the secured area and to the alarm cables.
How would it help to know the values of the resistors? The comparator in the alarm system will react to resistance changes within microseconds or at least milliseconds.
You won't be able to cut the cable and place a resistor between the wires in that time. And you can't pierce the wire and place a resistor in between before cutting: you'd parallel the resistors which is easily detectable by the comparator.
OK, let's assume that physical access to the wiring is possible, and that the alarm panel is sensing DC voltage levels. (Dave did mention multiplexing, but this should not be a problem provided it does not occur too quickly). Now, strip a length of one of the conductors, solder a small value resistor across, and then cut the wire bypassing the resistor. The resistor value is chosen to be small enough that it doesn't disturb the loop enough to trigger the alarm. (The end-of-line resistors will be 1% tolerance at best, so there should be some margin available).
The resistor can be used to sense the current flowing in the loop. This can be amplified with an op-amp, and imposed across the lines, effectively creating a synthetic resistor equal in value to the EOL resistor.
With the loop intact, the op-amp will not provide any output current. But as soon as the loop is cut, the op-amp will instantly take up the current that was flowing through the resistor. Provided that the system is fast enough, the alarm panel will not notice the difference. (The sensing circuit cannot be too quick to raise the alarm, otherwise it would be vulnerable to EMI)
Though, I expect anyone who could make this work has better things to be doing than breaking into houses...