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EEVblog #751 - How To Debunk A Product (The Batteriser)
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Muttley Snickers:

Either technically or morally the device appears to fall into a peculiar category.

http://en.wikipedia.org/wiki/Parasitism

Muttley
EEVblog:
Due to popular request I have a shorter and perhaps more digestible text based article here:
http://www.eevblog.com/2015/06/07/the-batteriser-explained/
Smokey:
Nice text article.  I'm interested to see if you get more exposure from that than the video.  I would think it would be way easier for a news site to use the text article as a source than pointing people to watch a video.  The text is more quotable and makes a better static reference.
BradC:
The section on rechargeables has me wondering. The theory on discharge down to 1V is to make sure the battery is not discharged to the point where individual weak cells can be reverse-charged. I've never heard any evidence to state that discharging a single cell to 0V will damage it, and in fact it is sometimes recommended to store NiCd & NiMh cells that have been properly discharged with shorting bars attached. I've certainly never damaged a cell by flattening it completely in isolation.

Discounting all the other failings of the product, if it can stop a rechargeable cell being reverse charged it's a bonus.
Wytnucls:

--- Quote from: 0xdeadbeef on June 07, 2015, 11:34:47 pm ---
--- Quote from: Wytnucls on June 07, 2015, 07:26:02 pm ---I just finished running a discharge test of a single Duracell AA battery, between 0.7V and 0.6V, with a constant resistive load (5.6 Ohms + test leads).
Initial discharge current was 100mA and at the end, 90mA. It took 1 hour and 5 minutes for the 0.1V discharge.
Assuming the discharge slope is constant between 1V and 0.6V, that would be 4 hours of extra battery time. Depending on the converter efficiency at 100mA, that time could be reduced significantly.

--- End quote ---
Well, 1st of all 400mAH is 20% of a 2000mAH cell. Not quite 800%.
Also keep in mind that even at ideal efficiency, the boost up of the voltage to 1.5V means that 100mA drawn from the boost up converter doesn't mean 100mA are drawn from the battery. Actually, at 0.7V more than 200mA are drawn which raises to 250mA at 0.6V. Obviously, considering a realistic efficiency, the current would be even higher. And higher currents means negative impact on battery life.

--- End quote ---
Well, first of all, I never said that 800% is a realistic figure.
I think 10 to 20% is plausible, depending on final efficiency. Assuming an efficiency of 80~90%, with a current draw of 100mA, 2~3 hours at 40-50mA is still useful for some devices. A multimeter, for instance, only uses 10mA of current on average. A couple of sleeves would be easier to carry around, than extra batteries. Definitely not a huge market, but a market nevertheless.
I don't know how the device works, but the IC could reduce final voltage to 1.2~1.3V at the low end and still have most devices working at that voltage.

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