Sorry Dave, at 4:50 you made an error of units in your calculation, mixing Energy and Power, or missing the evaluated time:
905kJ/l = 251Wh/l (not Watt/l).
So in 150 min = 2.5h, you would 'only' need a 100W panel.
This energy argument also is not directly convincing, if you think of physical 'heat pumps'.. (e.g. inversely running Sterling motor)
These machines have an efficiency, which is by definition >> 1, so you may pump these 905kJ out of the vapor by a fraction of equivalent in electrical energy, theoretically.
A practical machine of that sort (~ 40..60°C, 100% humidity) is the tumble dryer, which needs about 1.6kWh to condense several liters water out of the laundry.. if you have a modern device (EU energy rating A+++) with heat exchanger.
So the most obvious practical argument would be, that this device does not consist of the necessary miniaturized parts, like heat pump, condenser, heat exchanger, and so on.
Frank