| General > General Technical Chat |
| Electroboom: How Right IS Veritasium?! Don't Electrons Push Each Other?? |
| << < (32/148) > >> |
| PlainName:
--- Quote ---For a wire we can calculate the power, but we cant calculate the amps, koz we cant calculate the resistance. We don’t know what electric resistance iz or iznt. Hence there is no possible calculation from first principles. --- End quote --- For that matter, we (rather, you) don't know how electons stick to conductors and not non-conductors, so there is no possible calculation from first principles for electon theory either. |
| m k:
Better duplicate the middle wire and split the circuit so that GND is bottom of the higher part. Lower part remains below GND, its voltage is negative compared to GND. |
| electrodacus:
--- Quote from: dunkemhigh on July 02, 2022, 10:22:44 am ---Soz for the lengthy quote but I think this is a good post to fall back to. Perhaps the interested parties could just fill in appropriate values for voltage, resistance, current, etc., instead of rambling off about everyone else not understanding stuff. I've had a go. Isn't the circuit on the left essentially two separate circuits, each burning 1W? The circuit on the right is a single circuit burning 2W overall. But the currents and voltages across the resistors are the same in each. Suppose on the left you have just one circuit - let's delete the bottom battery, wires, resistor. So it is now a single circuit burning 1W. That top wire is passing 1A. On the right it is still passing 1A but the circuit is burning 2W, so how is that extra 1W getting around if the top wire is passing no more current (with no difference in voltage drop)? --- End quote --- I see that is not just hamster_nz that is confused. You seems to have the same confusion. The two circuits due to symmetry are not different in any way. From an electrical point of view they are identical as that wire in the middle has no electrical role (no current meaning no electrons flow through that wire). But I guess same as hamster_nz you agree with the above fact is just that you do not understand what power and energy is. Both power and energy are calculated and not measured. What you measure is just voltage (pressure will be the analog for fluids) even the current is not measured but calculated as the voltage drop on a length of wire with known resistance. Also just to be clear there is no current flow through that piece of wire connecting the GND symbol. One electron has a charge of about 1.6 * 10-19C So 1A for one second 1As a number of 1/1.6*10-19 = 6.25 * 1018 electrons flow each second trough that wire. That is a huge number of electrons that flow through the wire each second. So that number of electrons leave the negative of the bottom battery every second and travel all the way around the wires/resistors (wires and resistors are the same thing) and enters the positive of the top battery. At the same time same number of electrons leave the negative of the top battery and enter the positive of the bottom battery. The above is valid for both diagrams thus there is no difference between the two. |
| PlainName:
If you take two identical circuits (battery, resistor, 2 wires) which are not connected together, they each burn 1W. Now, if you connect the top wire of one to the bottom wire of the other, you have the circuit on the left. Now, you may say that the left circuit is identical to the right circuit, but in that case just pretend (to save having to draw it) that the left circuit is the two identical but separate circuits I just described. Don't we now have 2 x 1W circuits with 1A going through each of the top wires in one case, and in the other 1 x 2W circuit with 1A going through the sole top wire? |
| electrodacus:
--- Quote from: dunkemhigh on July 02, 2022, 04:51:11 pm ---If you take two identical circuits (battery, resistor, 2 wires) which are not connected together, they each burn 1W. Now, if you connect the top wire of one to the bottom wire of the other, you have the circuit on the left. Now, you may say that the left circuit is identical to the right circuit, but in that case just pretend (to save having to draw it) that the left circuit is the two identical but separate circuits I just described. Don't we now have 2 x 1W circuits with 1A going through each of the top wires in one case, and in the other 1 x 2W circuit with 1A going through the sole top wire? --- End quote --- You are confused by the fact that wires and resistors are the same thing. Also the "wires" in your diagram are superconductors meaning they have zero resistance to current flow. It will be useful if you make the drawing at scale and just use wires with say 1Ohm per some random unit of length that chose say 10cm or maybe 100pixels Then all the wires you use will have resistance and you will probably understand where your thinking is wrong. You should realize that the two schematics are the same. Or continue to use those superconductor wires but add a resistor for every wire you have. So in the schematic on the left you need to add 4 more resistors and on the one of the right 1 more resistor. |
| Navigation |
| Message Index |
| Next page |
| Previous page |