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Electroboom: How Right IS Veritasium?! Don't Electrons Push Each Other??
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electrodacus:

--- Quote from: hamster_nz on July 03, 2022, 02:14:00 am ---
No I am not. Draw the circuit out, and put arrows showing the flow of electrons in the wires. In one wire they flow from the battery to the lamp, in the other they flow from the lamp to the battery.

Energy only flows from the battery to the lamp.

--- End quote ---

Electrons flow out of the negative terminal and at the same time electrons from the wire flow in to the positive terminal so there is only one direction that electrons flow and that is from negative terminal in to the positive terminal.

Here is the animation I posted earlier
The negative terminal of that 9V battery is where the red wire is connected.
hamster_nz:

--- Quote from: electrodacus on July 03, 2022, 02:19:26 am ---
--- Quote from: hamster_nz on July 03, 2022, 02:14:00 am ---
No I am not. Draw the circuit out, and put arrows showing the flow of electrons in the wires. In one wire they flow from the battery to the lamp, in the other they flow from the lamp to the battery.

Energy only flows from the battery to the lamp.

--- End quote ---

Electrons flow out of the negative terminal and at the same time electrons from the wire flow in to the positive terminal so there is only one direction that electrons flow and that is from negative terminal in to the positive terminal.

Here is the animation I posted earlier
The negative terminal of that 9V battery is where the red wire is connected.


--- End quote ---

Black arrows are flow of electrons (from battery to load (bottom wire), and then from load to battery (top wire).

Red arrow is the net flow of energy (from battery to load).

In the top wire the electrons are flowing against the direction of energy flow.
electrodacus:

--- Quote from: hamster_nz on July 03, 2022, 02:28:42 am ---
Black arrows are flow of electrons (from battery to load (bottom wire), and then from load to battery (top wire).

Red arrow is the net flow of energy (from battery to load).

In the top wire the electrons are flowing against the direction of energy flow.

--- End quote ---

In that diagram just add a 2 Ohm resistor just after the negative terminal of the battery and say a 3Ohm resistor immediately at the positive terminal of the battery then show me how that read arrow is pointing.
That red arrow is just something you came out with it means nothing.
If the battery has say a 10Ohm internal DC resistance then how will that arrow point as 90% of the energy will be delivered inside the battery.
hamster_nz:

--- Quote from: electrodacus on July 03, 2022, 02:45:15 am ---
--- Quote from: hamster_nz on July 03, 2022, 02:28:42 am ---
Black arrows are flow of electrons (from battery to load (bottom wire), and then from load to battery (top wire).

Red arrow is the net flow of energy (from battery to load).

In the top wire the electrons are flowing against the direction of energy flow.

--- End quote ---

In that diagram just add a 2 Ohm resistor just after the negative terminal of the battery and say a 3Ohm resistor immediately at the positive terminal of the battery then show me how that read arrow is pointing.
That red arrow is just something you came out with it means nothing.
If the battery has say a 10Ohm internal DC resistance then how will that arrow point as 90% of the energy will be delivered inside the battery.

--- End quote ---

The battery is discharging  the resistor is getting hot. Energy is flowing from the battery to the resistor.

No additional components are needed. The red arrow is valid. Or if you want, you can redraw it with two smaller red arrows on the wires, showing the energy flow in each wire.
electrodacus:

--- Quote from: hamster_nz on July 03, 2022, 02:52:43 am ---
--- Quote from: electrodacus on July 03, 2022, 02:45:15 am ---
--- Quote from: hamster_nz on July 03, 2022, 02:28:42 am ---
Black arrows are flow of electrons (from battery to load (bottom wire), and then from load to battery (top wire).

Red arrow is the net flow of energy (from battery to load).

In the top wire the electrons are flowing against the direction of energy flow.

--- End quote ---

In that diagram just add a 2 Ohm resistor just after the negative terminal of the battery and say a 3Ohm resistor immediately at the positive terminal of the battery then show me how that read arrow is pointing.
That red arrow is just something you came out with it means nothing.
If the battery has say a 10Ohm internal DC resistance then how will that arrow point as 90% of the energy will be delivered inside the battery.

--- End quote ---

The battery is discharging  the resistor is getting hot. Energy is flowing from the battery to the resistor.

No additional components are needed. The red arrow is valid. Or if you want, you can redraw it with two smaller red arrows on the wires, showing the energy flow in each wire.

--- End quote ---

If in your diagram the battery had a 9Ohm internal DC resistance the wire will be close to zero so we ignore and the resistor 1Ohm then only 10% of the energy provided by the battery will end up where your red arrow is pointing with 90% delivered inside the battery so the opposite of where your red arrow is pointing.
The energy is delivered all around the closed loop as the black arrows show.
So say the DC resistance of the negative electrode was 4Ohms big part of the energy will be conducted and then radiated from there then at the same time on the positive electrode say 5Ohms even more energy is delivered there ending up heating the battery and a small part will be radiated by the 1Ohm resistor.
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