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| Electroboom: How Right IS Veritasium?! Don't Electrons Push Each Other?? |
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| electrodacus:
--- Quote from: dunkemhigh on July 03, 2022, 10:48:43 pm --- For one, as soon as you start using the capacitor energy the voltage drops and then you'll start demanding a graph of voltage over time and wibbling on about how the energy is depleting and... well, you have form, let's put it like that. For another the battey is going last a lot longer and give a steady output. That's all the reason the battery is there - it is a constant source. It's not ACTUALLY, a battery, but the circuit diagram doesn't have a symbol for a electrodacus-proof source, so that's the nearest we have. And, no. There is negligible internal resistance in this source, so forget about diverting to a discussion of that. --- End quote --- Voltage on any real battery will also drop and way less predictable. Depends on battery capacity, A capacitor can store as much energy as a battery. You see that is the problem. The battery being ideal with zero internal DC resistance and infinite capacity will look like magic and maybe understanding that part is important in understanding how energy is delivered to a load. The capacitor is also important to understand as it exists for any transmission line. Understanding that the two parallel wires form a capacitor and capacitors store electrical energy is relevant to understand why some current flows through the lamp well before electron wave can arrive there. In the SPICE simulation you do not define the length of the wire or distance between them yet by adding the appropriate inductance and capacitance you can simulate exactly what happens because line capacitance and inductance are a real thing. |
| PlainName:
--- Quote ---Why do you think my equation will be valid for a sail powered vehicle driving directly down wind but not for one that has a propeller installed and connected to wheels ? --- End quote --- I explained in the other thread, and amazingly that's when you took a sabbatical. Essentially, if the prop is turning then it is pushing air. If that stream of air is going backwards then the velocity of the vehicle is the speed of the wind PLUS the speed of that backwards-streaming air. Does your equation take account of that? Ergo it is not the right equation for this situation. |
| PlainName:
--- Quote from: electrodacus on July 03, 2022, 11:05:05 pm --- --- Quote from: dunkemhigh on July 03, 2022, 10:48:43 pm --- For one, as soon as you start using the capacitor energy the voltage drops and then you'll start demanding a graph of voltage over time and wibbling on about how the energy is depleting and... well, you have form, let's put it like that. For another the battey is going last a lot longer and give a steady output. That's all the reason the battery is there - it is a constant source. It's not ACTUALLY, a battery, but the circuit diagram doesn't have a symbol for a electrodacus-proof source, so that's the nearest we have. And, no. There is negligible internal resistance in this source, so forget about diverting to a discussion of that. --- End quote --- Voltage on any real battery will also drop and way less predictable. --- End quote --- I bloody well knew it!!! :horse: Repeat after me: it is a 1V constant voltage low impedance supply. I don't give a rats ass if it's a battery or a capacitor or the bloody national grid - it is a 1V constant voltage supply which happens to use a battery symbol for simplicity and comprehension. Right, so now try to answer the question asked rather than the on you would like to have been asked so you could rabbit on about 'energy storage'. |
| PlainName:
--- Quote ---In the SPICE simulation you do not define the length of the wire --- End quote --- You're a piece of work, eh. The wires are virtually non-existent. Zero length, as close as you can make them. Even if they were 10ft long (3m and a bit for the EU) whatever effect they could have would be NOTHING compared to the 1W burned up by the resistor, not the 1V of the supply. It seems that you cannot actually answer the question and instead just go off on the slightest thing as a diversion. [Edit: the connotations associated with a popular and slightly different version of that phrase are not what I intended, hence editing it out.] |
| electrodacus:
--- Quote from: dunkemhigh on July 03, 2022, 11:27:16 pm ---I explained in the other thread, and amazingly that's when you took a sabbatical. Essentially, if the prop is turning then it is pushing air. If that stream of air is going backwards then the velocity of the vehicle is the speed of the wind PLUS the speed of that backwards-streaming air. Does your equation take account of that? Ergo it is not the right equation for this situation. --- End quote --- Yes the equation (not mine used by many people around the world) will not account for stored energy. The equation provides you with the important wind power available to vehicle and you need a separate equation for the stored energy depending on the type of energy storage and how it is implemented. Propeller is an energy storage device. It is a flywheel but more importantly it creates a pressure differential between the front and back side of the swept area with is about 20m2 in case of blackbird. I explained all details in my video and even showed a graph showing how a direct downwind vehicle can exceed wind speed based on how much power is diverted to energy storage (propeller) instead of being used to accelerate the vehicle. |
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