| General > General Technical Chat |
| Funny little problem - can you answer? |
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| Benta:
--- Quote from: bdunham7 on May 04, 2022, 07:22:08 pm --- --- Quote from: Benta on May 04, 2022, 06:49:23 pm ---Why would a current source (the multimeter) cause induced currents? The logic fails me. --- End quote --- Van Allen belts, solar wind, rotating earth magnetic field, etc. --- End quote --- Totally irrelevant. Do you really think he meant "around the moon" in a literal sense? Which part of "let's say" is misunderstandable? The point was about an extremely long cable. Don't muddy the waters, please. |
| DavidAlfa:
A huge short, at least for a few days/weeks, until the cable charges up? As per 82pF/m, given 2c length (600*10⁹), capacitance would be 49.2F ! |
| Benta:
--- Quote from: DavidAlfa on May 04, 2022, 08:02:06 pm ---A huge short, at least for a few days/weeks, until the cable charges up? As per 82pF/m, given 2c length (600*10⁹), capacitance would be 49.2F ! --- End quote --- Who said the shield is connected? |
| magic:
Stop being practical. My guess: OP wants to hear 50Ω. |
| FriedMule:
I am sorry had to run out the door, and I am sorry for my badly formulated question. Let's say you had an Ohm meter that, let's say measures twice a second, it is able to measure the cables. You measure the center conductor. Your Ohm meter is not particular fantastic, so if you measure 1 inch or 10 inches will just be detected as about zero Ohms. I have deliberately chosen the RG58 because it is a general "standard" without being too technical in frequency, shielding or material. The question is mostly about what you would imagine your Ohm-meter will say when it returns a measuring result before the Ohm-meter's signal can have time to travel all the way. :-) |
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