Author Topic: lamp help  (Read 2205 times)

0 Members and 1 Guest are viewing this topic.

Offline grifftechTopic starter

  • Frequent Contributor
  • **
  • Posts: 369
  • Country: us
    • youtube channel
lamp help
« on: January 03, 2016, 05:47:49 am »
What voltage DC is equivalent to 130 volts AC for a lamp
 

Offline IanB

  • Super Contributor
  • ***
  • Posts: 12477
  • Country: us
Re: lamp help
« Reply #1 on: January 03, 2016, 05:51:46 am »
130 volts.
 

Offline grifftechTopic starter

  • Frequent Contributor
  • **
  • Posts: 369
  • Country: us
    • youtube channel
Re: lamp help
« Reply #2 on: January 03, 2016, 06:20:42 am »
Just and FYI, some of the new LED lights will not run from DC.    RMS is the equivalent DC.
incandescent.
 

Offline IanB

  • Super Contributor
  • ***
  • Posts: 12477
  • Country: us
Re: lamp help
« Reply #3 on: January 03, 2016, 06:28:12 am »
Just and FYI, some of the new LED lights will not run from DC.    RMS is the equivalent DC.
incandescent.

AC volts are the same as DC volts by definition.

However, incandescent lamps designed for AC may have a shorter life on DC due to filament migration.
 

Offline ajb

  • Super Contributor
  • ***
  • Posts: 2759
  • Country: us
Re: lamp help
« Reply #4 on: January 03, 2016, 08:16:30 pm »
Unless otherwise noted, AC voltage is specified in terms of the square root of the average of the squared voltage, or "root mean square"/RMS for short.  This is a useful way of specifying voltage because with many loads the amount of power applied to the load is proportional to the square of the voltage--so if you double the voltage, you quadruple the power.  So by specifying the RMS voltage, you're implicitly specifying a waveform that when applied to a resistive load would result in the same power being applied as an equal DC voltage.  So for a 130VAC lamp, you'd need 130VDC to run it at nominal power. 

It's worth noting that for common waveforms there are simple conversion factors to determine the peak voltage from the RMS village and vice versa--for a sine wave, Vpeak = Vrms * sqrt(2).  For more complex or nonrepetitive waveforms, you just have to measure a bunch of points, square them, average the squares, and then take the square root of the average.  Cheap ac-reading voltmeters do the former--measuring the peak voltage, and apply a factor that assumes a pure sine wave--, more expensive 'True RMS' meters effectively do the latter.
 


Share me

Digg  Facebook  SlashDot  Delicious  Technorati  Twitter  Google  Yahoo
Smf