Hello,
I don't have a lot of experience with oscilloscopes, but I did some measurements with analog ones.
I am considering buying a DSO (probably a Hantek DSO5062 or an equivalent), but one particular thing worries me about it.
Most of these cheap DSO have 8 bit ADCs.
Let's say that I have a 100kHz 5Vpp square wave with some ringing and I want to have a closer look at the ringing after the rising edge.
My question is - does the vertical position knob add a generated DC offset voltage between the signal source and the ADC or does it just move the same measurement across the screen?
If the first is true, then I can subtract for example 4.9V (with the vertical position knob) from the input signal and set the measurement range for 200mV, which would give me 0.8mV/bit for an 8 bit ADC - seems fine for watching a < 200mVpp ringing.
But if the second one is true, then ADCs 8bits would be spread across 5Vpp (assuming that the voltage range of the scope matches the waveform) which would mean that each bit is ~20mV and shifting the waveform and decreasing v/div only does a 'software zoom' - does not improve the viewing resolution. That could be a considerable disadvantage of a cheap DSO compared to a quality second hand analog scope.
thanks,
Filip