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Sharing some project planning phase: A (digital) ELECTRO-MECHANICAL Network

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RJSV:
   A chronological treatment is going to help for understanding over-all function, of these pipelined switch boxes:
   First diagram; From a box's point of view, an arriving 'SELECT', arrives, on the 'Local' or 'L-in' shaft.  That gets moved over, from left to right in diagram, resulting in driving the positioning 'motor' element of switch 'B'.
Looking up higher, straight above is the upper layer in this expanded view and that has the little toggle, that follows the lower toggle positioning .
The 'B' shaft is then going to drive anything, but for now the shaft is stopped (dry switching).
That's going to take some 300 mSec, nominal, for toggle travel.

RJSV:
   Readers should note that it's the 'A' shaft itself, that powers the SELECT action, (to SET the 'B' switch).  That is, from current (new) box point of view, the 'A' shaft actually starts up, rotating slightly before that SELECT starts coming in.  (More in a sec.)
   That's because the 'A' 'generic' shaft signal, when asserted, is there in all the boxes down the network line. (The other boxes are just not in selected mode.)
Note also: I corrected the 'A' switch position depicted, supposed to be in RESET position.
   Looking at the gear chain for the 'A' motor, that's shown with a marker pen set on those 4 gears. Ignore, please, the front little chain, (4 gears, they have a little paper slip along them). That was previously discussed.

RJSV:
(Previous diagram).
   Interesting, the 'main' just, of that gear chain, the 4 gears (underneath pen) form a path from the 'B' local output (that's just by turning the shaft, while selected, some custom connect), path to the 'A' motor input.
So that looks pretty 'normal', but hold on...:
   The upper, follower section, of 'B', sends down, and into this chain, but, ALREADY there is connection, to the gear that conveys an overflow...Maybe not obvious, but feels 'reckless', or like a:
'. '. MECHANICAL. SHORT. CIRCUIT ' '.

Uhhh, I think they call that a 'STALL', ...pretty sure.

RJSV:
   I'm assuming a (rotary) signal gets down the network line pretty quick, like 1 second or less. Assuming, say, 12 stations, each 2 feet apart.
In each station, that rotary signal gets thru in probably maximum 50 mSec.  Funny then, the nominal gear start-up or accelerate time is 10 mSec per gear, : That means significant time, especially with, let's say, 8 gears.  That's an 80 mSec time to start rotating at speed, and signifies how a switched signal can 'lag' in time, behind the 'raw' generic shaft (any of 'A', or 'B', or 'C' series BUS chain.

RJSV:
Let's stay on this TIMING thing, a bit more:
   So impulse #1, that was put into the 'Box Input', and goes, internally, directly to set (that box's) 'B' switch.
In the string or series string network, impulse #1 serves to SET the next box, from (expiring) current.
   
   Impulse #2, that's where channel 'B' outputs, again internally only, the 'command', as it were, to SET the 'A' switch.
I'm figuring, by the way, sending BASE CONTROLLER knows which station / which delay or pulse length, etc to use.
   At 50Sec. each, 4 stations should be OK at 200 mSec delay, before assuming you can start timing, plus whatever action time, for switching the network components, that it.
   So that is saying, at Station 4, when you want to impulse one of the internal switches, your Electric Motor impulse should last, at least 200 mSec + 300 mSec, for best reliable switching.
   So, STEP #3:). Now that channel 'B' had SET channel 'A' to active, and assuming you've done all of that 'custom' output from channel 'C', now it's time to send out, to next BOX, a SELECT for local hand-off.

Step #3 is kind of complicated:
   It sends, out via the 'LOCAL' shaft, to SELECT next
   It parallel sends, via LOCAL, to RESET the channel 'B' switch, right here in this box, but also,
   It uses the 'Saturation Overflow' to accomplish RESET
back around the loop, as that reset takes away the power that is doing all this (that's switch 'A' being active).

   So, that's a few steps, but, aside from any complexity with channel 'C', the actual impulses are simply, 'B', for 500 mSec and then 'A' for 500 mSec.
If no activity for 'C' output, it takes a pair of those, to get down to each next network box.

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