I have a question (or an observation) about stray voltage/stray capacitance that I can't quite answer/explain:
I have here a CD player (but it pretty much could be any other non earthed device) that has stray voltage on the rca out.
This is present when the device is turned on, but also when it's turned off (provided the plug is put in the mains socket in such a way that the live is connected to the transformer, not the on/off switch). (I'm in continental europe where you can plug in either way)
This stray voltage is (I presume) the consequence of parasidic/stray capacitance.
And this stray voltage can be measured anywhere in the device, so on every IC pin, capacitor, the motorleads of the cd tray etc.
However, when de device is turned on, that stray voltage is considerably lower than when it's turned off.
At first I measured it with a digital/LCD voltage tester (similar to the one BigClive tested on youtube:
https://youtu.be/uT-OwmLkpx4), when the device is turned off, it registers almost 110v (between the 55v and 110v marker), when turned on, it registers about 36V), I did a µA current measurement (to earth pin), where when the device is turned off, a greater AC current runs (about 3,5µA) than when the device is turned on (about 1,5µA AC), and I did a normal AC voltage measurement (to earth pin) where the voltage is also considerably higher when the device is turned off (53Vac), than it's turned on(33Vac).
So I was wondering why.
Because this stray voltage is present everywhere in both on and off position, I can't imagine this is due to the internal circuitry of the device itself (say the DC part).
I understand that with different measurement methods you will measure different voltages because the resistance value to ground with that measurement varies depending on what measurement you're doing, but it seems to be very consistent that there is a significantly higher stray voltage is present when the device is off than when it's on, regardless of the type of measurement.
The only/main reason that I can think of why this is, is that the transformer forms a stray capacitor (the first one seen from the mains outlet), where the primary winding is one conductor of the stray capacitor, and the secondary winding is the other conductor.
When the device is turned off, the complete primary winding (which now is 1 long ending wire) has a 230V voltage (to ground) along the complete length.
But when the device is turned on, the other side of the primary winding is of course connected to neutral. So the voltage on that primary winding starts from 230V (on the live side) to 0V on the neutral side, so there's a complete voltage drop over that primary winding and therefore the net (or average) voltage on that wire is much less.
So that the difference in stray voltage in the device between On state and Off state is not the result of what the internal circuitry is doing differently when its on compared to when its off, but that the difference in stray voltage is a result of that the initial average offered voltage (over that primary coil) is lower in ON state than in OFF state.
Does that make any sense or is the theory behind my explanation and findings all wrong and something else causes the difference in stray voltage between on and off state?
I couldn't find anything about this phenomenon in my search.